Physics, asked by aakinsheck, 7 months ago

write the integration of sine squarex dx​

Answers

Answered by mehulsolanki194
3

Use the half angle formula, sin^2(x) = 1/2*(1 - cos(2x)) and substitute into the integral so it becomes 1/2 times the integral of (1 - cos(2x)) dx. Set u = 2x and du = 2dx to perform u substitution on the integral.

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Answered by ratanhantal81
0

Answer:

Step 1 Use the half angle formula, sin^2(x) = 1/2*(1 - cos(2x)) and substitute into the integral so it becomes 1/2 times the integral of (1 - cos(2x)) dx. Step 2 Set u = 2x and du = 2dx to perform u substitution on the integral. Since dx = du/2, the result is 1/4 times the integral of (1 - cos(u))

Explanation:

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