Question

write the isomers of the compound having formula C4H9Br ?

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Answer 1

Answer:

There is four isomers of the given compound. Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b).

Explanation:

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Answer 2

Answer:

4 isomers

Explanation:

For the compound C₄H₉Br 4 structural isomers are possible.

They are:

1. 1-bromo butane ⇒ CH₃-CH₂-CH₂-CH₂-Br
2. 2-bromo butane ⇒ CH₃-CH₂-CH(Br) -CH₃
3. 1-bromo-2-methyl propane ⇒ CH₃-CH(CH3) -CH₂-Br
4. 2-bromo-2-methyl propane ⇒ CH₃-(CH₃)C(Br) -CH₃

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