Question

write the IUPSC name of following.
note= see the question by opposite side​

Answer 1

Answer:

aap upse kr rahe ho

Explanation:

I don't know

Answer 2

Answer:

IUPAC names of the given molecules:

CH₃COCH₂COOH           3-Oxobutanoic acid

CH₃CH(Cl)CH₂CHO         3-Chlorobutanal

CH₃CH(OH)CH(Br)CHO   2-Bromo-3-hydroxybutanal

Explanation:

1. The parent chain contains four carbon atoms (word root: But), and two functional groups(COOH, CO). In this case, COOH has a higher priority than CO, so the compound name end with -oic acid. The keto group is considered as a substitute on the third C and is added as a prefix (-oxo). The answer is 3-Oxobutanoic acid.
2. Here functional group aldehyde gets more priority than halogen. Numbering will start from -CHO and -Cl become substitute on 3rd C. Your answer is 3-Chlorobutanal.
3. Here functional group priority is as follows: -CHO > -OH > -Br. The numbering starts from -CHO. The aldehyde group is added as a suffix (-al) while the other two as prefixes (-OH - hydroxy; -Br -Bromo). The prefixes are arranged in alphabetical order along with their position. Your answer is 2-Bromo-3-hydroxybutanal.