Question

Write the law of Biot-Savart and with the help of this law derive
an expression of the intensity of the magnetic field at the centre of
circular coil carrying current.​

Answer 1

Answer:

First lows of motion in ss

Answer 2

Answer:

μ04π is the constant of proportionality , here μ0 is the permittivity of free space. Therefore, the magnetic field on the axis of a circular loop is μ0IR22(x2+R2)32. Note: When the value of x becomes zero, we get the expression for the magnetic field at the centre of the loop.