Math, asked by dharmshil, 1 year ago

write the laws of eexponent for real no.

Answers

Answered by Shreya980429
0
am *an = am+n
am/an=am-n
(am)n=amn
am*bm=m(a*b)
a0=1
Answered by Salmonpanna2022
1

Step-by-step explanation:

Low of Integral Exponents

For any two real numbers a and b, a, b ≠ 0, and for any two positive integers, m and n

➲ If a be any non - zero rational number, then

a^0 = 1

➲ If a be any non - zero rational number and m,n be integer, then

(a^m)^n = a^mn

➲ If a be any non - zero rational number and m be any positive integer, then

a^-m = 1/a^m

➲ If a/b is a rational number and m is a positive integer, then

(a/b)^m = a^m/b^m

➲ For any Integers m and n and any rational number a, a ≠ 0

a^m × a^n = a^m+n

➲ For any Integers m and n for non - zero rational number a,

a^m ÷ a^n = a^m-n

➲ If a and b are non - zero rational numbers and m is any integer, then

(a+b)^m = a^m × b^m

I hope it's help you...☺

:)

Similar questions