Math, asked by aryankumarsharma, 1 year ago

write the laws of exponents


aryankumarsharma: hi

Answers

Answered by saranya14
3
hey friend here is your answer
a^m×a^n=a^m+n,
a^m/a^n =a^m-n(m>n),1/a^n-m(n>m),
a^0=1
a^m=a^n,m=n
a^m=x^m,a=x
(a^m)n=a^mn

Answered by christinsiby7
0

Answer:

x^{1} = x

x^{0}  = 1

x^{-1} = 1/x

x^{m}x^{n} = x^{m+n}

x^{m} x^{n} = x^{m-n}

(x^{m})^{n} = x^{mn}

xy^{n} = x^{n}  y^{n}

(x/y)^{n} = x^{n}/y^{n}

x^{-n} = 1/x^{n}

x^{m/n} = \sqrt[n]{x^{m} } = (\sqrt[n]{x})^{m}

Step-by-step explanation:

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