Question

write the least number which when divided by 15,24,36 and 72 leaves the remainder 9 in each case​

Answer 1

Answer:

369

Step-by-step explanation:

First we have to find the LCM of 15, 24, 36 and 12

First we have to find the LCM of 15, 24, 36 and 12 LCM of 15, 24, 36 and 12 is 360

First we have to find the LCM of 15, 24, 36 and 12 LCM of 15, 24, 36 and 12 is 360 360 + 9 = 369

The least number which on dividing by 15, 24, 36 and 72 leaves the remainder 9 in each case is is 369.

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Answer 2

Answer:

369

Step-by-step explanation:

First we find the LCM of 15, 24, 36 and 72

$\left[\begin{array}{cccc}15&24&36&72\\5&8&12&24\\5&4&6&12\\5&4&2&4\\5&2&1&2\\5&1&1&1\\1&1&1&1\end{array}\right]$

= 3x2x3x2x2x5= 360

As we want the remainder to be 9, we add 9 to the LCM

= 360 + 9

= 369