Question

Write the line segment joining the points (5, -6) and (1, -4) to be divided in the ratio? Also find the coordinates of this resistance point.​

Answer 1

Step-by-step explanation:

Using the section formula, if a point (x,y) divides the line joining the points (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then

(x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

Let the point on y -axis be P(0,y) and

AP:PB=k:1

Therefore, using section formula:

k+1

5×1+(−1)×k

=0

5−k=0

⟹k=5

Hence, required ratio is 5:1.

Now,

y=

5+1

(−4)×5+(−1)×6

=

6

−20−6

=

3

−13

Hence, point on y -axis is P(0,

3

−13

)