Question

write the linear equation 3x+2y=18 in the form of ax+by+c=0,also write the values of a,band c.Are(4,3)and (1,2) solutions of this equation?

Answer 1

3x+2y-18=0
a=3, b=2 & c=-18

(4,3) is the solution of this equation.

Answer 2

The values are a = 3,  b = 2 and c = - 18

(4, 3) is solution of the equation but (1, 2) is not solution of the equation

Given:

3x+2y=18 is a Linear equation .

Can be written as 3x+2y-18 = 0

To Find:

Given equation is in the form of ax+by+c=0 then find values of a, b, c

Check if (4,3)and (1,2) are solutions of given equation

Solution:

Compare given equation 3x+2y-18 = 0 with ax+by+c=0  

From above  ⇒ a = 3,  b = 2 and c = - 18  

Now check if (4,3) and (1,2) are solutions of 3x+2y=18

If given points are solution of the linear equation then they must satisfy the given equation

For (4, 3)

Substitute (4, 3) in given equation

3x+2y=18 = 3(4) +2(3) = 18

⇒  12 + 6 = 18      

⇒ 18 = 18              

Here (4, 3) will satisfy the equation

⇒ (4, 3) is solution of the equation 3x+2y=18

For (1, 2)

Substitute (1, 2) in given equation

3x+2y=18 = 3(1) +2(2) = 18

⇒  3 + 4 = 18      

⇒ 7 $\neq$ 18              

Here (1, 2) will not satisfy the equation

⇒ (1, 2) is not solution of the equation 3x+2y=18

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