Question

Write the linear equation in two variables to represent the statement, “Cost of 7 oranges

exceeds the cost of 1 dozen of bananas by 24 rupees”. If the cost of 1 banana is 5 rupees

then find the cost of 1 orange

Answer 1

Step-by-step explanation:

let x be cost of oranges and y be cost of banana

then, 7x = 12y + 24

=> 7x - 12y - 24 = 0 Equation

now cost of one banana = Rs 5

to find cost of one oranges

=> 7x - 12*5 - 24 = 0

=> 7x = 24 + 60

=> 7x = 84

=> x = 84/7 = 12

therefore cost of one orange = x = Rs 12

Answer 2

Step-by-step explanation:

Let the cost of one orange and banana be x and y respectively.

A.to.q

7x-12y=24-----(i)

A.to.q

Cost of one banana is ₹5=y

Then the cost of one dozen bananas =12y=12×5=₹60.

Putting the value of 12y in eqn (I)

7x-12y=24

7x-60=24

=>7x=24+60

=>7x=84

=>x=84÷7=₹12

There fore the cost of one is ₹12.