Question

write the linear equation x+√3y=4 in the form of ax+by+c=0 & hence write the values of a, b,c and write x in term of y
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Answer 1

Answer:

x+√3y-4=0

a=1, b=√3, c=-4

x=4-√3y

Step-by-step explanation:

ax+by+c=0

x+√3y-4=0

a=1

b=√3

c=-4

x+√3y=4

x=4-√3y

Answer 2

$= ax + by + c = 0$

$= x \sqrt{ } 3y - 4 = 0$

$= a = 1$

$= b = \sqrt{3}$

$= c = - 4$

$= x + \sqrt[]{3y} = 4$

$= x = 4 - \sqrt[]{3y}$

$= x + \sqrt[ ]{3y} - 4 = 0$

$= a = 1b = \sqrt[]{3} c = - 4$

$= x = 4 - \sqrt{3y}$