Question

Write the linear equation x/4 = 1 - y/6 in the standard form draw its graph and find the point where the graph of above equation cuts the x-axis​

Answer 1

Step-by-step explanation:

this is your answer

the linear equation is equal to x axis 6

Answer 2

Given :  linear equation x/4 = 1 - y/6

To Find : standard form

Draw graph

the point where the graph cuts the x-axis​

Solution:

Standard form of linear equation in two variable is

Ax + By + C = 0

x/4 = 1 - y/6

Multiplying both sides by 12

=> 3x = 12 - 2y

=> 3x + 2y - 12 = 0

3x + 2y - 12 = 0  is Standard form

To Draw graph :

x = 0   =>  y  = 6   point ( 0 , 6)

y = 0 =>  x  = 4    point ( 4 , 0)

Plot these points and draw a line passing through points.

cuts the x-axis​ at ( 4 , 0)

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