Question

Write the linear equation x/4 = 1 - y/6 in the standard form draw its graph and find the point where the graph of above equation cuts the x-axis​​

Answer 1

Answer:

Given 3x+2y+6=0

⟹2y=−6−3x

⟹y=−3−

2

3

x

To draw the graph , we need atleast two solutions

Also to find the coordinates of the points where the graph cuts the coordinate axes,put x=0 and y=0 respectively

Put x=0 in (1)

⟹y=−3−

2

3

(0)=−3−0=−3

(0,−3) is the solution of given line

Put y=0

⟹0=−3−

2

3

x

⟹

2

3

x=−3

⟹x=−2

(−2,0) is the solution of given line

With these two solutions we can draw linear graph of 3x+2y+6=0

(−2,0) & (0,−3) are the points where the graph cuts the coordinate axes