Question

write the lowest rationalising factor of √24​

Answer 1

Answer:

plzz follow

Step-by-step explanation:

Here's your answer..

Here's your answer..____________________

Here's your answer..____________________\begin{lgathered}\sqrt{24} = \sqrt{2 \times 2 \times 3 \times 2} \\ thus \: here \: 2 \: has \: got \: a \: pair \: so \: we \: can \: remove \: one \: of \: them \\ \\ so \: \sqrt{24} = 2 \sqrt{6}\end{lgathered}

Here's your answer..____________________\begin{lgathered}\sqrt{24} = \sqrt{2 \times 2 \times 3 \times 2} \\ thus \: here \: 2 \: has \: got \: a \: pair \: so \: we \: can \: remove \: one \: of \: them \\ \\ so \: \sqrt{24} = 2 \sqrt{6}\end{lgathered} 24

Here's your answer..____________________\begin{lgathered}\sqrt{24} = \sqrt{2 \times 2 \times 3 \times 2} \\ thus \: here \: 2 \: has \: got \: a \: pair \: so \: we \: can \: remove \: one \: of \: them \\ \\ so \: \sqrt{24} = 2 \sqrt{6}\end{lgathered} 24 plzzz follow

=

= 2×2×3×2

= 2×2×3×2

= 2×2×3×2

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthem

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24 =2

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24 =2 6

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24 =2 6

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24 =2 6

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24 =2 6

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24 =2 6

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24 =2 6 ____________________

= 2×2×3×2 thushere2hasgotapairsowecanremoveoneofthemso 24 =2 6 ____________________HOPE IT HELPS..

Answer 2

Hii !!

√24

step 1: Took LCM

2|24

2|12

2|6

3|3

|1

step 2: put it under the root

√2×2×2×3

step 3: Simplify till last

2√6

step 4: Identify the rationalising factor

Lowest rationalising factor for √24 is √6.

Hope it helps you !!