Math, asked by kaviraj84680, 7 months ago

Write the Maclaurin’s series
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Answers

Answered by btsarmy0779
8

Answer:

As the Maclaurin series for cosx is ∞∑n=0(−1)nx2n(2n)!, we can write: cos2x=∞∑n=0(−1)n(2x)2n(2n)! =∞∑n=0(−1)n22nx2n(2n)!. cos2x=1+cos2x2=1+∞∑n=1(−1)n22n−1x2n(2n)!.

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