Question

Write the main product when Ethanal reacts with hydrazine?? if u answer it correct I will mark you as brainliest.​

Answer 1

Answer:

Explanation:

Aldehydes and ketones having at least one α-hydrogen undergo a reaction in the presence of dilute aqueous caustic soda as catalyst to form α-hydroxy aldehydes (aldol). This is known as aldol reaction.

Acetaldehyde

2CH  

3

​  

−CHO

​  

 

→

Dil.NaOH

 

3−hydroxybutanal

CH  

3

​  

−  

OH

∣

​  

 

C

​  

H−CH  

2

​  

−CHO

​  

 

Δ

→

​  

 

H  

+

 

​  

 

But−2−enal

CH  

3

​  

−CH=CH−CHO

​  

 

(b) The carbonyl group of acetaldehyde reacts with hydrazine to produce a hydrazone in which the carbon is double bonded to nitrogen.

(c) When acetaldehyde is warmed with freshly prepared ammoniacal silver nitrate solution, a bright silver mirror is produced. The aldehyde gets oxidized to acetate ion and silver ion is reduced to metallic silver.

CH  

3

​  

CHO+2[Ag(NH  

3

​  

)  

2

​  

]  

−

+3OH  

−

→  

Acetateion

CH  

3

​  

COO  

−

 

​  

+  

(silvermirror)

2Ag

​  

↓+2H  

2

​  

O+4NH  

3

​  

 

Acetaldehyde on reaction with Phosphorus pentachloride, gives gem-dichloride.

Acetaldehyde

CH  

3

​  

CHO

​  

+  

pentachloride

Phosphorus

​  

 

PCl  

5

​  

 

​  

→  

gem−dichloride

CH  

3

​  

CHCl  

2

​  

 

​  

+POCl  

3

​  

.

Answer 2

Answer:

$answer = > \ \: When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.</u></em></strong></p><p></p><p><strong><em><u>[tex]answer = > \ \: When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.C2H5−CHO+2CH3OHHCl(1,1−diethoxy propane)C2H5−CH(OCH3)2</u></em></strong></p><p></p><p><strong><em><u>[tex]answer = > \ \: When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.C2H5−CHO+2CH3OHHCl(1,1−diethoxy propane)C2H5−CH(OCH3)2(ii) Propanal having α-hydrogen atom undergo aldol condensation in presence of dil. NaOH and forms 3-hydroxy-2-methyl pentanal.</u></em></strong></p><p></p><p><strong><em><u>[tex]answer = > \ \: When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.C2H5−CHO+2CH3OHHCl(1,1−diethoxy propane)C2H5−CH(OCH3)2(ii) Propanal having α-hydrogen atom undergo aldol condensation in presence of dil. NaOH and forms 3-hydroxy-2-methyl pentanal.C2H5−CHO+(dilute)NaOH⟶C2H5−OH∣CH−CH∣CH3−CHO</u></em></strong></p><p></p><p><strong><em><u>[tex]answer = > \ \: When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.C2H5−CHO+2CH3OHHCl(1,1−diethoxy propane)C2H5−CH(OCH3)2(ii) Propanal having α-hydrogen atom undergo aldol condensation in presence of dil. NaOH and forms 3-hydroxy-2-methyl pentanal.C2H5−CHO+(dilute)NaOH⟶C2H5−OH∣CH−CH∣CH3−CHO(iii) The carbonyl group of propanal is reduced to CH2 group on treatment with hydrazine followed by heating with KOH in ethylene glycol and the product formed will be propane.</u></em></strong></p><p></p><p><strong><em><u>[tex]answer = > \ \: When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.C2H5−CHO+2CH3OHHCl(1,1−diethoxy propane)C2H5−CH(OCH3)2(ii) Propanal having α-hydrogen atom undergo aldol condensation in presence of dil. NaOH and forms 3-hydroxy-2-methyl pentanal.C2H5−CHO+(dilute)NaOH⟶C2H5−OH∣CH−CH∣CH3−CHO(iii) The carbonyl group of propanal is reduced to CH2 group on treatment with hydrazine followed by heating with KOH in ethylene glycol and the product formed will be propane.C2H5−CHONH2−NH2−H2OC2H5−C∣∣N−NH2KOH/ethylene glycolheatC2H5−CH3+N2</u></em></strong></p><p></p><p><strong><em><u>[tex]answer = > \ \: When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.C2H5−CHO+2CH3OHHCl(1,1−diethoxy propane)C2H5−CH(OCH3)2(ii) Propanal having α-hydrogen atom undergo aldol condensation in presence of dil. NaOH and forms 3-hydroxy-2-methyl pentanal.C2H5−CHO+(dilute)NaOH⟶C2H5−OH∣CH−CH∣CH3−CHO(iii) The carbonyl group of propanal is reduced to CH2 group on treatment with hydrazine followed by heating with KOH in ethylene glycol and the product formed will be propane.C2H5−CHONH2−NH2−H2OC2H5−C∣∣N−NH2KOH/ethylene glycolheatC2H5−CH3+N2Answered By</u></em></strong></p><p></p><p><strong><em><u>[tex]answer = > \ \: When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.C2H5−CHO+2CH3OHHCl(1,1−diethoxy propane)C2H5−CH(OCH3)2(ii) Propanal having α-hydrogen atom undergo aldol condensation in presence of dil. NaOH and forms 3-hydroxy-2-methyl pentanal.C2H5−CHO+(dilute)NaOH⟶C2H5−OH∣CH−CH∣CH3−CHO(iii) The carbonyl group of propanal is reduced to CH2 group on treatment with hydrazine followed by heating with KOH in ethylene glycol and the product formed will be propane.C2H5−CHONH2−NH2−H2OC2H5−C∣∣N−NH2KOH/ethylene glycolheatC2H5−CH3+N2Answered By$

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