Write the mass of calcium carbonate formed when 44g of CO2 is reacted with 56g of quick lime.
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.1 mole of Cao and CO2 gives one mole CaCO3
CaO+CO2 ---->CaCO3
Now 1 mole CaO is 56 g.
And 1 mole CO2 is 44g .
So it will give 1 mole CaCO3 i.e. 100g CaCO3...
CaO+CO2 ---->CaCO3
Now 1 mole CaO is 56 g.
And 1 mole CO2 is 44g .
So it will give 1 mole CaCO3 i.e. 100g CaCO3...
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The answer is 100g or 1 mole
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