Question

Write the mathematical relationship between Joule and erg?​

Answer 1

An erg is the amount of work done by a force of one dyne exerted for a distance of one centimeter. In the CGS base units, it is equal to one gram centimeter-squared per second-squared (g. cm2/s2). It is thus equal to 10−7 joules or 100 nanojoules (nJ) in SI units.

Answer 2

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Here,

$1J = \frac{1kg\: {m}^{2} }{ {s}^{2} }$

$1J = 1kg \times \frac{1m \times m}{ {s}^{2} }$

$1J = \frac{1000gm \times 100cm \times 100cm}{ {s}^{2} }$

$1J = 10000000 \frac{gm \: {cm}^{2} }{ {s}^{2} }$

$1\:erg = {10}^{ - 7} Joules$

$So, \: 1\:erg = {10}^{ - 7} Joules$