Math, asked by tanmayvirmani, 2 days ago

Write the maximum number of zeroes of the polynomial (3y²+32y +y³+20)(y-1).

Answers

Answered by poonam847211devi
0

(3y²+32y +y³+20)(y-1)

=3y³+32y²+y⁴+20y-3y²-32y-y³-20

= y⁴+2y³+29y²-12y-20

Since the degree of the given polynomial is 4 , so it will have maximum 4 zeros.

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