Write the mechanism of the following
reaction :
CH3 -CH2 - Br+KOH (alc)-
CH2=CH2 +KBr +H2O
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Answer:
mechanism
Explanation:
CH3-CH2-Br + KOH(alc) -------- CH2=CH2
when ethyl bromide react with alcoholic KOH the first CH3-CH2-Br break down according to markonic's off and then OH attached and after self reaarengement H-OH will release and form CH2=CH2
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