Write the mid point theorum completely.
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statement :The line segment joining the mid point of any 2 side of a triangle is parallel to the third side and equal to half of it.
Step-by-step explanation:
- Given, In tri ABC D and E are mid point of side AB and AC. construction :extend AB to F so that DE =EF. To prove :DE=1/2BC and DE //BC. proof :IN tri ade and cef
- <aed =<cef (vertically opposite angle
- ae=ce (e is mid point
- de=ef(construction
- ade congruent to triangle cef (sas rule
- ad=cf(cpct
- <adf=<cfe (cpct 1)
- ad=bd(d is mid point 2)
- from 1and 2
- bd=cf
- bd//cf
- in quadrilateral bcfd
- bd=cf
- bd//cf(3)
- so bcfd is parallel ogram
- bc=fd and bc//df (opposite side of parallelogram
- 1/2bc=1/2df
- 1/2bc=de and bc//df
- de=1/2bc and bc//de
- hope it helps
- mark it as brainliest
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