Question

Write the midpoint of the line segment joining the points P(x1,y1) and Q(x2,y2).​

Answer 1

Answer:

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the midpoint of the line segment joining the points P (x1, y1) and q (x2 , y2) is ([x1+x2]/2, [y1+y2]/2)

As we know the mid point between two points 'a' and 'b' is (a+b)/2, similarly,

For finding out the mid point of line segment joining two points (x1, y1) and (x2, y2) will be ([x1+x2]/2, [y1+y2]/2)

Eg. If the two points are (2, 4) and (6,8), then the mid point of the line segment joining them would be:

([2+6]/2, [4+8]/2) = (4,6)

Answer 2

Topic:-

Co-Ordinate Geometry

Question:-

What is the mid point of the line segment joining the points P(x1,y1) and Q(x2,y2).

Solution:-

We know that Mid point formula=

$\dfrac{x1+x2}{2} and \dfrac{y1+y2}{2}$

Here the Given points are P=(x1,y1) and Q=(x2,y2)

So, The mid point of the given points is

$\dfrac{x1+x2}{2} and \dfrac{y1+y2}{2}$

Answer:-

$\dfrac{x1+x2}{2} and \dfrac{y1+y2}{2}$

More Information:-

Centroid :-

The point of intersection of three medians in a triangle is called Centroid

Incentre :-

The point of conccurence of internal angular bisectors is called Incentre

Excentre :

The point of concurrence of 1 internal angular bisector 2 External angular bisectors is called excentre

Circumcentre :-

The point of intersection of perpendicular bisectors of triangle is called circumcentre

Orthocentre :

The altitude of triangle are concurrent and their point of concurrence is called Orthocentre

Distance formula:-

$\bf\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Centroid formula:-

$\bf\dfrac{x_1+x_2+x_3}{3},\bf\dfrac{y_1+y_2+y_3}{3}$

Section formula Internal division:-

$\bf\dfrac{mx_2+nx_1}{m+n}, \bf\dfrac{my_2+ny_1}{m+n}$

Section formula External division

$\bf\dfrac{mx_2-nx_1}{m-n}, \bf\dfrac{my_2-ny_1}{m-n}$

These are the some important terms that You have to remember