Write the MO configuration of N2 molecule and calculate the bond order
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The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.
The total number of electrons present in the nitrogen molecule (N2) is 14.
Nb = 10
Na = 4
Bond order = (Nb−Na) /2
B.O = (10−4)/2
B.O = 3
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