Question

Write the molecular and possible structural
formula of the first four members of
homologous series of carboxylic acids​

Answer 1

Answer:

here is ur answer ...!!

The general molecular formula for carboxylic acids is CnH2n+1COOH. Carboxylic acids contain at least one carboxyl group. ... The first four carboxylic acids derived from alkanes are methanoic acid (HCOOH), ethanoic acid (CH3COOH), propanoic acid (C2H5COOH) and butanoic acid (C3H7COOH).

Explanation:

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Answer 2

In this question, we are asked to write the molecular and possible structural formula of the first four members of the homologous series of carboxylic acid.

• Having the same functional group and similar properties, homologous series are a group of organic compounds in which each member differs from the others by a common repeating unit. CH2
• The various individuals that make up the homologous sequence are known as homologs.
• The same general formula can be used to describe all members of the series, and they can all be created using nearly identical techniques known as general methods of preparation.
• As the molecular mass increases, there is a progressive gradation in the physical characteristics of the members of these series.
• Carboxylic acid's standard molecular formula is CₙH₂ₙ₊₁ COOH
• The first four carboxylic acid homologous series members

• HCOOH   (Formic acid)
• CH₃COOH (Ethanoic acid/ Acetic acid)

• C₂H₅COOH (Propanoic acid)

• C₃H₇COOH (Butanoic acid)

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