Write the molecular electronic configuration of F2 and C2. Draw the energy level diagram. Calculate the bond order and explain its magnetic property?
Answers
F2 the following: (sigma 2s)^2. (sigma 2s*)^2. (sigma 2px)^2. (pi 2py)^2
Acc to molecular orbital theory…. Sigma 1s2 sigma1 1s*2 sigma2s2 sigma 2s*2 pi 2pz2 (assuming intermolecular axis be z) nd pi2py 1 nd pi2px1.
C2
Bond order is the number of Chemical bonds between a pair of atoms and indicates the stability of a bond.
In a Covalent Bond ( as in case of C2 ) between two atoms, a single bond has a bond order of one, a double bond has a bond order of two, a triple bond has a bond order of three, and so on. There are various methods to determine the bond order between two covalently bonded atoms.
The First Method Is As Follows;
Draw the Lewis Structure.
Determine the type of bonds between the two atoms.
0: No bond
1: Single bond
2: double bond
3: triple bond
If The Bond Order is Zero Then The Molecule Can't Be Formed.
So in C2;
We can see both the Carbons are Doubly bonded,thus the Bond Order in C2 = 2.
In The Sceond Method We Follow The Molecular Orbital Theory & Calculte The Numbers Of Bonded ( Nb ) & Non-Bonded Electrons ( Na ).
The Fourmula Is: (Nb - Na)/2…
The Case Occurring In C2 Is Shown In The Figure Above no.3...
F2
The atomic number of fluorine is 9, so a (neutral) F2 molecule has a total of 18 electron, or 14 valence electrons (excluding the four 1s electrons). The (F2)- ion has one more valence electron, or 15. The orbital diagram for a diatomic molecule is
To find the bond order, add the 15 electrons in the molecular orbitals (the blue-colored energy levels in the diagram) one at a time until you have used them up. They completely fill all the orbitals except the highest-energy antibonding sigma 2p orbital. Thus, there will be 8 bonding electrons and 7 antibonding electrons, leavig a net ofonly one bonding electron. The bond order = (net bonding electrons)/2 = 0.5.
see figure above no.4
