Write the molecular formula of 2nd and 3rd member of homologous series whose first member is ethyne.
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The general formula of homologous series whose first member is ethyne is
CnH2n-2,
Then two consecutive number of 2nd and 3rd member of homologous series
CH3-CH ( Propyene) n is 3
CH3CH2C- CH (2-Brutyne) n is 4
Hence the molecular formula is
C3H4 and C4H6
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