Write the molecular formula of 4th and 5th members of the homologous series having functional group as bromine
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Bromomethane and Bromoethane
Anonymous:
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Members of the homologous series
The homologous series starts from methane .
➡ Methane .
➡ Ethane .
➡ Propane .
➡ Butane .
➡ Pentane .
4 th member is Butane .
5 th member is Pentane .
Molecular formula of bromides
Butane = C₄ H ₁₀
Pentane = C₅ H ₁₂
Remove 1 H for 1 Br and we are done !
Butyl bromide = C₄ H₉ Br
Pentyl bromide = C₅ H₁₁ Br
That's the perfect formula .
Hope it helps !
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