write the multiples of 13 that are between 100 and 150
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The first number between 100 & 300 divisible by 13 is 104 & the last is 299.
So by the concept of AP.
An= A+(n-1)d
299=104+(n-1)13
195=(n-1)13
15=(n-1)
n=16
Or
n=(299/13)—(104/13)+1
n=23–8+1
n=16
Answered by
0
Answer: 8,9,10 and 11 are the multiple of 13.
Step-by-step explanation:
We have to find multiple of 13 which should be lie between the 100 and 150-
By the table of 13
- 13 ×1 = 13 ( multiple of 13 but not lie between the value of 100-150)
- 13 ×2 = 26 ( multiple of 13 but not lie between the value of 100-150)
- 13 ×3 = 39 ( multiple of 13 but not lie between the value of 100-150)
- 13 ×4 = 52 ( multiple of 13 but not lie between the value of 100-150)
- 13 ×5 = 65 ( multiple of 13 but not lie between the value of 100-150)
- 13 ×6 = 78 ( multiple of 13 but not lie between the value of 100-150)
- 13 ×7 = 91 ( multiple of 13 but not lie between the value of 100-150)
- 13 ×8 = 104 (multiple of 13 which is lie between 100-150)
- 13 ×9 = 117 (multiple of 13 which is lie between 100-150)
- 13 ×10 = 130 (multiple of 13 which is lie between 100-150)
- 13 ×11 = 143 (multiple of 13 but not between 100-150).
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