Math, asked by adharshvijay408, 7 months ago

write the multiples of 7in between 200 and 500. what are the first and last number? find the sum of all numbers in this sequence.​

Answers

Answered by sukhpreet066sukh
1

Answer:

15050

Step-by-step explanation:

7×29=203

7×30=210

7×31=217

7×32=224

7×33=231

7×34=238

7×35=245

7×36=252

7×37=259

7×38=266

7×39=273

7×40=280

7×41=287

7×42=294

7×43=301

7×44=308

7×45=315

7×46=322

7×47=329

7×48=336

7×49=343

7×50=350

7×51=357

7×52=364

7×53=371

7×54=378

7×55=385

7×56=392

7×57=399

7×58=406

7×59=413

7×60=420

7×61=427

7×62=434

7×63=441

7×64=448

7×65=455

7×66=462

7×67=469

7×68=476

7×69=483

7×70=490

7×71=497

First number =203

Last number=497

Total 15050

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