Question

write the n,l,m for electron present in 2Pz orbital​

Answer 1

Answer:

For  2pz,

n = 2

l= 1

m= 0

Explanation:

n is principle quantum number, for 2pz it is 2. As the shell number is 2.

l is azimuthal quantum number, for 2pz it is 1. As the value of azimuthal quantum number for p sub shell is always 1.

m is magnetic quantum number, for 2pz it is 0.

As the orbital angular momentum has no component along z - axis and have it must become zero and therefore to make L=0, we must take m=0.

Answer 2

Answer:

if n=2

l= n-2

2-1

1

hope this helps you my friend

please mark as brainliest answer