Question

Write the name and the formula of the two cmpound formed when ester ch3cooc2h5 undergoes saponification

Answer 1

CH3COOH (ETHANOIC ACID)and C2H5OH(ETHANOL OR ETHYL ALCOHOL)ARE THE TWO COMPOUNDS FORMED WHEN ESTER UNDERGOES SAPONIFICATION.

Answer 2

Names of the product  formed by saponification of $CH_3COOC_2H_5$.

• When ester is treated with bases it leads to the formation of alcohol and sodium salt of carboxylic acid. This process is called as saponification.
• When compound such as $CH_3COOC_2H_5$ is treated with NaOH which is a base, it yields ethanol and sodium ethanoate as product.
• Among the product formed, ethanol is alcohol whereas sodium ethanoate is sodium salt of carboxylic acid.
• The balanced chemical equation involved in saponification of $CH_3COOC_2H_5$ is as follows:

$CH_3COOC_2H_5+NaOH\rightarrow C_2H_5OH+CH_3COONa$

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