Question

Write the name of reducing agent and the compound undergoing reduction in the following equations: i. CuO + H2 + heat ----> Cu+ H2O ii. ZnO + C ----> Zn + CO iii. 3MnO2 + 4Al ----> 3Mn + 2Al2O3​

Answer 1

Answer:

1. Cu undergoes reduction since its loses oxygen. Loss of oxygen is reduction.H2 gains oxygen.  It is oxidized. Hence it is the reducing agent.

2. Zn loses oxygen. It undergoes reduction. C gains oxygen. Hence it is oxidized and acts as a reducing agent.

3. 3Mn loses oxygen. It is reduced. 2Al gains oxygen. It is oxidized. Hence it acts as a reducing agent.

Explanation:

Answer 2

Explanation:

i. CuO + H2 + heat -----------> Cu + H2O

in this reaction CuO is undergoing reduction as the removal os oxygen is occuring and H2 is the reducing agent as it reduces CuO by taking oxygen from it.

ii. ZnO + C ---------> Zn + CO

in this reaction ZnO is undergoing reduction as oxygen is being removed and C is the reducing agent as it reduces Zn by taking oxygen from it.

iii. 3MnO2 + 4Al ---------> 3Mn + 2Al2O3

in this reaction 3MnO2 is undergoing reduction as oxygen is being removed and Al is the reducing agent as it takes oxygen from Mn.