Question

write the name of the element present in the given compound and the calculate the molar masses 1. quicklime and 2.baking powder​

Answer 1

For quick lime it's Cao. For baking powder NaHCO3.

Answer 2

A) QUICK LIME or CALCIUM OXIDE

$cao$

The elements present are :-

1)Calcium
Atomic mass = 40 u

2) Oxygen
Atomic mass = 16 u

So,

Molecular mass of Calcium oxide is :-

$40 + 16 = 56 \: u$

So,

The molar mass will be equal to 56 grams

B) BAKING POWDER or SODIUM BI CARBONATE


The elements present are :-

1)sodium
Atomic mass = 23 u

2) Hydrogen
Atomic mass = 1 u

3) carbon
Atomic mass= 12 u

4) Oxygen
Atomic mass = 16 u

Molecular mass of NaHCO3 is :-

$23 + 1 + 12 + (16 \times 3) \\ \\ = 24 + 12 + 48 \\ \\ = 24 + 60 \\ \\ = 84 \: u$

So,

The Molar mass will be equal to 84 grams