Question

Write the nationalising factor of the
denominator in 1/√2+√3​

Answer 1

Answer:

$\frac{1}{ \sqrt{2} + \sqrt{3} } = \sqrt{2} + \sqrt{3}$

Step-by-step explanation:

$\frac{1}{ \sqrt{2} + \sqrt{3} } \\ = \frac{1}{ \sqrt{2} + \sqrt{3} } \times\frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3}} \\ = \frac{1( \sqrt{2} - \sqrt{3}) }{( \sqrt{2} + \sqrt{3} )( \sqrt{2} - \sqrt{3} )} \\ = \frac{ \sqrt{2} - \sqrt{3} }{ {( \sqrt{2}) }^{2} - {( \sqrt{3}) }^{2} } \\ = \frac{ \sqrt{2} - \sqrt{3} }{2 - 3} \\ = \frac{ \sqrt{2} - \sqrt{3} }{( - 1)} \\ = \frac{ \sqrt{2} - \sqrt{3} }{( - 1)} \times \frac{( - 1)}{( - 1)} \\ = \frac{ - \sqrt{2} - \sqrt{3} }{1} \\ = - \sqrt{2} - \sqrt{3} \\ = \sqrt{2} + \sqrt{3}$