Question

Write the nature of most of the quadratic
equation ax²-3 bx-4a=o (a = 0​

Answer 1

Explanation:

b^2 - 4×a×c

= (-3b)^2 - 4 × a × (-4a)

= 9b^2 + 16a^2

if a = 0 (Given)

= 9b^2 + 0

= 9b^2

b value will be always positive (If b ≠ 0)

So, 9b^2 › 0 & if b = 0 then 9b^2 = 0

So,the nature of this quadratic equation will be always Real.