write the nature of roots of quadratic equation 2×2 -5×+ 6=0
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2x^3 - 5x + 6 =0
discriminant = b^2 -4ac
= (-5)^2 -(4)(2)(6)
= 25 - 48
= - 23
This quadratic equation has no solution as it's discriminant is negative.
discriminant = b^2 -4ac
= (-5)^2 -(4)(2)(6)
= 25 - 48
= - 23
This quadratic equation has no solution as it's discriminant is negative.
Answered by
0
here
discriminant(D) = (-5)^2 - 4×2×6
= 25 -48 = - 23
since the value of discriminant is negative hence,
this quadratic eq have no real roots.
Rather there are two non real (distinct) complex roots. as follows
x= -(-5)/2×2 + i ( √-(-23) / 2×2 )
=5/4 +i (√23 / 4 )
and x = 5/4 - i (√23 / 4 )
discriminant(D) = (-5)^2 - 4×2×6
= 25 -48 = - 23
since the value of discriminant is negative hence,
this quadratic eq have no real roots.
Rather there are two non real (distinct) complex roots. as follows
x= -(-5)/2×2 + i ( √-(-23) / 2×2 )
=5/4 +i (√23 / 4 )
and x = 5/4 - i (√23 / 4 )
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