write the nature of roots of quadratic equation 4x2+6x+3=0
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Answer:
a=4
b=6
c=3
b2-4ac
(6)2-4(4)(3)
36-4(12)
36-48
-12<0
therefore it is imaginary
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b²-4ac
b=6
C=3
A=4
=6²-4(4)(3)
=36-48
=-12
It have imaginary root as discriminant is in negative
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