Question

Write the Nature of roots of Quadratic equation x^2-x-6=0​

Answer 1

Answer:

the equation have real distinct roots

Step-by-step explanation:

x^2-x-6

D=b^2-4ac

1-4(-6)

1+25

26

Answer 2

Step-by-step explanation:

x²-x-6=0

comparing with ax²+bx+c=0

a=1

b=-1

c=-6

hence ,

b²-4ac=(-1)²-4×1×(-6)

=1+24

=25

hence,

b²-4ac>0

nature of roots is real and unequal.

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