Math, asked by nagarajurapthadu, 8 months ago

write the nature of roots of Quadratic equation x2-x-6=0

Answers

Answered by Anonymous

6

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♤ ANSWER :- ♤

${x}^{2} - x - 6 = 0 \\ \\ {x}^{2} - 3x + 2x - 6 = 0 \\ \\ x(x - 3) + 2(x - 3) = 0 \\ \\ (x - 3)(x + 2) = 0 \\ \\ x =3 \\ \\ x = - 2$

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Answered by kailashmeena123rm

22

ANSWER

SINCE DISCRIMINENT = 1-4(1)(-6)= 25

which is positive

so equation has two real distinct roots

know other conditions

if discriminent is 0

then equation has two equal roots

because by quadratic formula

x= -b + √D /2a

where a and b are coefficient of x^2 and x

if D = 0 then clearly equation has two equal roots

if discriminent is negative then equation has two imaginary roots
if discriminent is a perfect square then roots are ratinal in nature
know set of complex nber > set of real >set of ratinal numbers

hope it helps

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