Question

write the nature of roots of the qadratic eqation xsqare-8x+16​

Answer 1

Answer:

x^2- 8x+16= 0

a= 1, b= -8, c= 16

D= b^2-4ac

= (-8)^2- 4(16)(1)

= 64- 64

= 0

SINCE D= 0

ROOTS ARE EQUAL AND REAL

Step-by-step explanation:

Answer 2

ans.0

Step-by-step explanation:

x.sq −8x+16=0

Discriminant is

(−8).sq −4×1×16=64−64=0

Since the discriminant is zero, the quadratic equation has equal and real roots.