Question

Write the nature of roots of the quadratic equation:-
$4x {}^{2} + 6x + 3 = 0$
​

Answer 1

EQ : 4X² + 6X + 3

a= 4 ,

b = 6 ,

c = 3

D = b²- 4 ac = 6² - 4×4×3 = 36 - 48

D= -12

therefore D < 0

(◍•ᴗ•◍)❤

you can clearly see that nature of roots is negative,(◍•ᴗ•◍)❤

so,D< 0

Answer 2

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${\underline {\underline {\star{given}}}}$

$4 {x}^{2} + 6x + 3 = 0.$

where as ,

a = 4 , b = 6. and c = 3.

Now Find the nature of roots

$d = {b}^{2} - 4ac \\ \\ \rightarrow \: {6}^{2} - 4 \times 4 \times 3. \\ \\ \rightarrow 36 - 48. \\ \\ \rightarrow \: - 12.$

D < 0

you can clearly see the Nature of roots be negative so,

It have Unreal Roots.

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