write the nature of the root of the quadratic equation 2xsquare-3x+1=0
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Answered by
1
a=2 b=-3 c= 1
b²-4ac= 9-8= 1
Since b²-4ac>0, two distinct real roots are formed
Answered by
3
Answer:
B square-4ac
3×3-4×2×1
9-8
1>0
So exist real and distinct roots.
Step-y-step explanation:
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