Question

write the nature of the roots of the quadratic equation 2x^2-3x+1=0​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer: 1

Step-by-step explanation:

$2x^{2} -3x+1$

comparing equation  with $ax^{2} +bx+c=0$

$a= 1 , b= -3 , c = 1$

we know that ,

$D = b^{2} - 4ac$

          =$(-3)^{2}-4(2)(1)$

         =$9-8$

         = 1

since $D\geq 0$

there are 2 distant real roots