Question

write the nature of the roots of the quadratic equation 9x² - 6x - 2 = 0. if it exists find the roots​

Answer 1

Answer:

imaginary

Step-by-step explanation:

b²-4ac<0 then the roots are imaginary

Answer 2

Answer:

a = 9 , b = -6 and c = -2

D = b² - 4ac

So, D = (-6)² - 4(9)(-2) = 36 + 72 = 108

Since, D > 0

⇒ Roots are Real and different.

Step-by-step explanation:

nature of the roots depend on the value of discriminant,

1.If D > 0,then roots are real and different.

2.If D = 0,then roots are real and same.

3.If D < 0, then roots do not exist or it is a complex number...