write the nernst equation and calculate the emf of cell at 298K.
Ni(s)| Ni^2+ (0.160M)|| Ag + (0.002M)| Ag
Given Ecell=1.05V
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Step-by-step explanation:
Answer:Given that
[Ag+] = 0.002 M
[Ni2+] =0.160 M
n = 2
Apply the Nernst equation:
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