Question

Write the Nernst equation and calculate the emf of the following cell at 298 K.

Cu (s) / Cu++ ( 0.130 M) // Ag+ ( 1.0× 10-4 M) / Ag (s) given : E Cu++ / Cu = 0.34V and E Ag+/Ag = 0.80V

Answer 1

The Nernst equa: Cu(s) | Ag+ ( 1.0× 10-4 M) || Cu++( 0.130 M) | Ag(s)

catot: Ag+ +1e -> Ag

anot: Cu -> Cu++ +2e

The emf: E(Cu-Ag) = E Ag+/Ag - E Cu++ / Cu = 0,8 - 0,34 = 0,46V

Answer 2

Explanation:

nerst equation

E = E • - 0.059/2 log cu^2+/(Ag^+)^2