Write the Nernst equation and ecell and calculate the emf of the following cell at 298 K.
Cu (s) / Cu++ ( 0.130 M) // Ag+ ( 1.0× 10-4 M) / Ag (s) given : E Cu++ / Cu = 0.34V and E Ag+/Ag = 0.80V
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Mg(s) +Cu2+(aq)? Mg2+(aq) + Cu(s)
Nernst equation
http://ncerthelp.com/scienceimg/12-CH3/03.jpg
There are two electron are transferring so that n = 2
E�cell = E� right� � E�left
E�cell =+0.34 � (�2.37)V
E�cell =+2.71V
Plug the value we get
Concentration of solid substance is 1 always so that [Mg] = [Cu] =1
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