Question

Write the Nernst equation for the following half-reaction and find E when pH =3.00 andPAH, =1.00 mbar.As(s) + 3HⓇ +3e AsH2(g); E° =-0.238 V​

Answer 1

Answer:

Write the Nernst equation for the following half-reaction and find E when pH =3.00 and PAH, = 1.00 mbar . As(s) + 3HⓇ +3e AsH2(g); E° =-0.238 V.

Answer 2

Explanation:

Write the Nernst equation for the following half-reaction and find E when pH = 3.00 and PAsH3 = 1.00 mbar. As(s) + 3H+ + 3e-↔ AsH3(g) E° = -0.238 V E = E° - (0.05916/3)log{PAsH3/[H+]3} = -0.238 V – 0.01972log{[1.00 mbar/(1013mbar/atm)]/(10-3)3} = -0.238 V – 0.01972log[(0.000987 atm)/10-9] = -0.238 V – 0.1182 V =

.

-0.356 V