Math, asked by AmanVibhash4366, 1 year ago

Write the no. Of zeros in end of a number whose prime factorization is 2^2×5^3×3^2×17

Answers

Answered by mysticd
2

Answer :

2 zeroes

Explanation:

2^2×5^3×3^2×17

= ( 2²×5²)×5×3²×17

= 100 × 5×3²×17

= 5×3²×17×100

The no. Of zeros in end of a number whose prime factorization is 2^2×5^3×3^2×17

= 5×3²×17×100

2 zeroes

••••

Answered by ChromaticSoul
2

We have,

2² × 5³ × 3² × 17

2² × 5² × 5 × 3² × 17

(2 × 5)² × 5 × 3² × 17

(10)² × 5 × 3² × 17

100 × 5 × 3² × 17

Clearly, there are two zeros at the end of the given number.

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