Write the no. Of zeros in end of a number whose prime factorization is 2^2×5^3×3^2×17
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Answered by
2
Answer :
2 zeroes
Explanation:
2^2×5^3×3^2×17
= ( 2²×5²)×5×3²×17
= 100 × 5×3²×17
= 5×3²×17×100
The no. Of zeros in end of a number whose prime factorization is 2^2×5^3×3^2×17
= 5×3²×17×100
2 zeroes
••••
Answered by
2
We have,
2² × 5³ × 3² × 17
2² × 5² × 5 × 3² × 17
(2 × 5)² × 5 × 3² × 17
(10)² × 5 × 3² × 17
100 × 5 × 3² × 17
Clearly, there are two zeros at the end of the given number.
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