Math, asked by akakakak6810, 11 months ago

Write the no. Of zeros in the end of a number whose prime factorization is 2²× 5³×3²×17

Answers

Answered by brunoconti
2

Answer:

Step-by-step explanation:

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Answered by ankurbadani84
0

Answer:

2 zeroes  - number of zeroes in the end of a number whose prime factorization is 2^2*3^2*5^3*17

Step-by-step explanation:

To find the number of zeroes at the end of the number formed we first need to find the number.  

Performing the operations we have :

2² × 3² × 5³ × 17 = 76500

The number formed by the product of the prime factors above is 76500.

We can now count the number of zeroes at the end of this number.  

The number of zeroes at the end of this number are two.  

So there are 2 zeroes.

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